In the diagram, \(\overline{MN}\)//\(\overline{PQ}\), < MNP = 2x, and < NPQ = (3x - 50)°. Find the value of < NPQ

  • A 200\(^o\)
  • B 100\(^o\)
  • C 120\(^o\)
  • D 90\(^o\)
waec 2020mathematics

The correct answer is B. 100\(^o\)

2x = 3x - 50 alternate angle 

50\(^o\) = 3x - 2x 

50\(^o\) = x 

< NPQ = (3x - 50)\(^o\) 

= 3(500)\(^o\) - 50 

= 150 - 50 = 100\(^o\)

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