Factorize 6pq-3rs-3ps+6qr

  • A 3(r -p)(2q + s)
  • B 3(p + r)( 2q - 2q - s)
  • C 3(2q - s)(p + r)
  • D 3(r - p)(s - 2q)
waec 2021mathematics

The correct answer is C. 3(2q - s)(p + r)

6pq-3rs-3ps+6qr = 3 (2pq - rs - ps + 2qr)

= 3 ({2pq + 2qr} {-ps - rs})

= 3 (2q{ p + r} -s{p + r})

= 3 ({2q - s}{p + r})

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