Simplify \(\frac{2-18m^2}{1+3m}\)

  • A 2[1+3m]
  • B 2[1-3m]
  • C 2[1-3m\(^2\)]
  • D 2[1+3m\(^2\)]

The correct answer is B. 2[1-3m]

\(\frac{2-18m^2}{1+3m}\) =  \(\frac{2[1-9m^2]}{1+3m}\)

\(\frac{2[1-3m][1+3m]}{1+3m}\)

2[1-3m]

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