In the diagram O is the center of the circle, if ∠QRS = 62o, find the value of ∠SQR.

  • A 14o
  • B 28o
  • C 31o
  • D 45o
  • E 90o
waec 1989mathematics

The correct answer is B. 28o

< QSR = 90° (angle in a semi-circle)

\(\therefore\) < SQR = 180° - (90° + 62°)

= 28°

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