If log x = \(\bar{2}.3675\) and log y = 0.9750, what is the value of x + y? Correct to three significant figures

  • A 1.18
  • B 1.31
  • C 9.03
  • D 9.44
  • E 9.46
waec 1990mathematics

The correct answer is E. 9.46

log x = \(\bar{2}.3675\) ; log y = 0.9750

\(x = 10^{\bar{2}.3675} = 0.02331 \)

\(y = 10^{0.9750} = 9.441 \)

\(x + y = 9.4641 \approxeq 9.46\)

Previous question Next question