If log x = \(\bar{2}.3675\) and log y = 0.9750, what is the value of x + y? Correct to three significant figures
The correct answer is E. 9.46
log x = \(\bar{2}.3675\) ; log y = 0.9750
\(x = 10^{\bar{2}.3675} = 0.02331 \)
\(y = 10^{0.9750} = 9.441 \)
\(x + y = 9.4641 \approxeq 9.46\)
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