Find the value of m which makes x\(^2\) + 8 + m a perfect square

  • A 2
  • B 4
  • C 8
  • D 12
  • E 16
waec 1990mathematics

The correct answer is E. 16

x\(^2\) + 8 + m

To make it a perfect square, we add \((\frac{b}{2})^2\)

= \((\frac{8}{2})^2\)

= 16

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