Two groups of male students cast their votes on a particular proposal. The result are as follows:<table border=\"1\" cellpadding=\"0\" cellspacing=\"0\" style=\"width:40%\"><tr><td> </td><td>In favor</td><td>Against</td></tr><tr><td>Group A</td><td>128</td><td>32</td></tr><tr><td>Group B</td><td>96</td><td>48</td></tr></table>If a student in favor of the proposal is selected for a post, what is the probability that he is from group A?

Two groups of male students cast their votes on a particular proposal. The result are as follows: In favor Against Group A 128 32 Group B 96 48 If a student in favor of the proposal is selected for a post, what is the probability that he is from group A?

Two groups of male students cast their votes on a particular proposal. The result are as follows:

If a student in favor of the proposal is selected for a post, what is the probability that he is from group A?

The correct answer is A. 8/19

Probability that a student in favor is group A

= \(\frac{128}{128 + 32 + 96 + 48}\)

= \(\frac{128}{304}\)

= \(\frac{8}{19}\)