If events X and Y are mutually exclusive, P(X) = 1/3 and P(Y) = 2/5, P(X∪Y) is

  • A o
  • B 2/15
  • C 4/14
  • D 11/15
  • E 1
waec 1991mathematics

The correct answer is D. 11/15

P(X \(\cup\) Y) = \(\frac{1}{3} + \frac{2}{5}\)

= \(\frac{11}{15}\)

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