A sector of a circle of radius 9cm subtends angle 120° at the centre of the circle. Find the area of the sector to the nearest cm\(^2\) [Take π = 22/7]

  • A 75cm2
  • B 84cm2
  • C 85cm2
  • D 86cm2
  • E 95cm2
waec 1993mathematics

The correct answer is C. 85cm2

Area of a sector = θ/360 x πr\(^2\)

= 120/360 x 22/7 x 81/1

= 84.86 cm\(^2\)

\(\approxeq\) 85cm\(^2\) (to the nearest cm)

Previous question Next question