From a set \(A = [3, \sqrt{2}, 2\sqrt{3}, \sqrt{9}, \sqrt{7}]\), a number is selected at random. Find the probability that is a rational number

  • A \(\frac{1}{5}\)
  • B \(\frac{2}{5}\)
  • C \(\frac{3}{5}\)
  • D \(\frac{4}{5}\)
waec 1999mathematics

The correct answer is B. \(\frac{2}{5}\)

\(A = {3, \sqrt{2}, 2\sqrt{3}, \sqrt{9}, \sqrt{7}}\)

n(A) = 5

Let the rational nos = R

n(R) = 2 (3, \(\sqrt{9}\))

P(R) = 2/5

Previous question Next question