A group of 11 people can speak either English or French or Both. Seven can speak English and six can speak French. What is the probability that a person chosen at random can speak both English and French?

  • A \(\frac{2}{11}\)
  • B \(\frac{4}{11}\)
  • C \(\frac{5}{11}\)
  • D \(\frac{11}{13}\)
waec 1999mathematics

The correct answer is A. \(\frac{2}{11}\)

Let the number of people that speak both English and French = x

Then (7 - x) + x + (6 - x) = 11

13 - x = 11 \(\implies\) x = 2.

\(\therefore\) P(picking a person that speaks both languages) = 2/11

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