Simplify \(\frac{4}{x+1}-\frac{3}{x-1}\)

  • A \(\frac{x+7}{x^2 - 1}\)
  • B \(\frac{x-7}{x^2 + 1}\)
  • C \(\frac{x-7}{x^2 - 1}\)
  • D \(\frac{x-11}{x^2 - 1}\)
waec 1999mathematics

The correct answer is C. \(\frac{x-7}{x^2 - 1}\)

\(\frac{4}{x+1}-\frac{3}{x-1} \\

=\frac{4x - 4 - 3x - 3}{(x+1)(x-1)}=\frac{x-7}{x^2 - 1}\)

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