The diagram shows the position of three ships A, B and C at sea. B is due north of C such that |AB| = |BC| and the bearing of B from A = 040°. What is the bearing of A from C

The diagram shows the position of three ships A, B and C at sea. B is due north of C such that |AB| = |BC| and the bearing of B from A = 040°. What is the bearing of A from C

A 040^o
B 070^o
C 110^o
D 290^o

waec 1999 mathematics

The correct answer is D. 290^o

< ABC = 40Â° (alternate angles)

\(\therefore\) < ACB = \(\frac{180Â° - 40Â°}{2}\)

= 70Â°

\(\therefore\) Bearing of A from C = 360Â° - 70Â°

= 290Â°

Previous question Next question