The reactance in an AC circuit can be calculated using the formulas for inductive reactance \(X_L = 2\pi fL\) and capacitive reactance \(X_C = 1/(2\pi fC)\), where \(f\) is the frequency, \(L\) is the inductance, and \(C\) is the capacitance.

Given that \(f = 500/\pi\) Hz, \(L = 0.9\) H, and \(C = 2 \times 10^{-6}\) F, we can calculate:

 Inductive Reactance: \(X_L = 2\pi (500/\pi)(0.9) = 900 \Omega\)
  
Capacitive Reactance:  \(X_C = 1/(2\pi (500/\pi)(2\times10^{-6})) \approx 500 \Omega\)

Since the inductor and capacitor are in parallel, the total reactance \(X_T\) is the difference between the inductive and capacitive reactance:

\(X_T = X_L - X_C = 400 \Omega\)