How long will it take to heat 3 kg of water from 28<sup>o</sup>C to 88<sup>o</sup>C in an electric taking a current of 6 A from an e.m.f. source of 220V?

How long will it take to heat 3 kg of water from 28oC to 88oC in an electric taking a current of 6 A from an e.m.f. source of 220V?

How long will it take to heat 3 kg of water from 28^oC to 88^oC in an electric taking a current of 6 A from an e.m.f. source of 220V?

The correct answer is C. 570s

Ivt = mcÎÎ¸

t = mcÎÎ¸/Iv = 3x 4200 x (88 - 28)/6 x 200