A rocket is launched from the surface of the earth. If the radius of the earth is 6.4 x 106m and the acceleration of free fall due to gravity is 1Oms-1 calculate the escape velocity of the rocket.

  • A 2.53 x 104ms-1
  • B 1.13 x 104ms
  • C 8.00 x 103ms-1
  • D 4.23 x 103ms-1
  • E 6.41 x 104ms-1

The correct answer is B. 1.13 x 104ms

V = √2gR

V = √2 x 10 x 6.4 x 102

1.13 x 104ms

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