2H\(_2\) + O\(_2\) → 2H\(_2\)O
From the equation above, calculate the volume of unreacted oxygen gas if a mixture of 50cm\(^3\) of hydroden and 75cm\(^3\) of oxygen are involved
The correct answer is B. 50cm\(^3\)
Since 2 mol H\(_2\) reacted with 1 mol of O\(_2\)
: 50cm\(^3\) of hydrogen reacted with 25cm\(^3\) of oxygen
Remainder oxygen = Supplied amount - Reacted amount â 75cm\(^3\) - 25cm\(^3\)
= 50cm\(^3\)
Previous question Next questionWhat is Exam without Practice? With our customizable CBT practice tests, you’ll be well-prepared and ready to excel in your examsStart Practicing Now