2H\(_2\) + O\(_2\) → 2H\(_2\)O

From the equation above, calculate the volume of unreacted oxygen gas if a mixture of 50cm\(^3\) of hydroden and 75cm\(^3\) of oxygen are involved

  • A 85cm\(^3\)
  • B 50cm\(^3\)
  • C 125cm\(^3\)
  • D 55cm\(^3\)
jamb 2022chemistry

The correct answer is B. 50cm\(^3\)

Since 2 mol H\(_2\) reacted with 1 mol of O\(_2\)

: 50cm\(^3\) of hydrogen reacted with 25cm\(^3\) of oxygen

Remainder oxygen = Supplied amount - Reacted amount â†’ 75cm\(^3\) - 25cm\(^3\)

= 50cm\(^3\)

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