An organic compound contains 69% carbon, 15.3% hydrogen and 30.7% oxygen. Calculate the the empirical formula [C=12, H = 1, O = 16]

  • A C\(_4\)H\(_12\)O
  • B C\(_3\)H\(_9\)O
  • C C\(_4\)H\(_9\)O
  • D C\(_3\)H\(_8\)O

The correct answer is D. C\(_3\)H\(_8\)O

C  \(\frac{69}{12}\)   H  \(\frac{15.3}{1}\)     O  \(\frac{30.7}{16}\)

C = 5.75,  H = 15.3,  O = 1.92

C \(\frac{5.75}{1,92}\)    H  \(\frac{15.3}{1.92}\)     O  \(\frac{1.92}{1.92}\)

C\(_3\)H\(_8\)O

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