The model height and range of heights 1.35, 1.25, 1.35, 1.40, 1.35, 1.50, 1.35, 1.50, and 1.20 are m and r respectively. Find m+2r.
The correct answer is C. 1.95
To find \(m + 2r\), we first need to calculate the mean (average) height and the range of heights.
Mean Height (\(m\)):
\[
m = \frac{1.35 + 1.25 + 1.35 + 1.40 + 1.35 + 1.50 + 1.35 + 1.50 + 1.20}{9}
\]
Calculate the sum of the heights:
\[
\text{Sum} = 1.35 + 1.25 + 1.35 + 1.40 + 1.35 + 1.50 + 1.35 + 1.50 + 1.20 = 12.25
\]
Divide by the number of heights (9):
\[
m = \frac{12.25}{9} = 1.3611 \approx 1.36
\]
Range of Heights (\(r\)):
The range of heights is the difference between the maximum and minimum heights:
\[
r = \text{Maximum Height} - \text{Minimum Height}
\]
Sort the heights in ascending order:
1.20, 1.25, 1.35, 1.35, 1.35, 1.40, 1.50, 1.50, 1.35
Maximum Height = 1.50
Minimum Height = 1.20
\[
r = 1.50 - 1.20 = 0.30
\]
Now, compute \(m + 2r\):
\[
m + 2r = 1.36 + 2 \times 0.30 = 1.36 + 0.60 = 1.96
\]
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