For what values of y is the expression \(\frac{6y-1}{y^2 - y-6}\)

  • A \(\frac{1}{6}, \frac{1}{4}\)
  • B 3, -2
  • C -3, 2
  • D 0,1
waec 2005mathematics

The correct answer is B. 3, -2

The expression is not defines when y2 - y - 6 = 0

=> y2 - 3y + 2y - 6 = 0 => (y-3)(y+2) = 0 => y

-3 = 0 or y + 2 = 0 => y = 3 or -2

Previous question Next question