The table shows the distribution of goals scored by 25 teams in a football competition. Calculate the probability that a team selected at random scored at most 3 goals.

  • A \(\frac{3}{25}\)
  • B \(\frac{1}{5}\)
  • C \(\frac{6}{25}\)
  • D \(\frac{2}{5}\)

The correct answer is D. \(\frac{2}{5}\)

No. of teams that scored at most 3 goals = 3 + 1 + 6 = 10

Hence, probability that a team selected at random scored at most 3 goals

= \(\frac{10}{25}\) = \(\frac{2}{5}\)

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