Expression 0.612 in the form \(\frac{x}{y}\), where x and y are integers and y \(\neq\) 0

  • A \(\frac{153}{250}\)
  • B \(\frac{68}{111}\)
  • C \(\frac{61}{100}\)
  • D \(\frac{21}{33}\)
waec 2018mathematics

The correct answer is A. \(\frac{153}{250}\)

0.612 = \(\frac{0.612}{1}\) x \(\frac{1000}{1000}\)

= \(\frac{612}{1000}\)

= \(\frac{153}{250}\)

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