Evaluate; \(\frac{\log_3 9 - \log_2 8}{\log_3 9}\)

  • A -\(\frac{1}{3}\)
  • B \(\frac{1}{2}\)
  • C \(\frac{1}{3}\)
  • D -\(\frac{1}{2}\)
waec 2019mathematics

The correct answer is D. -\(\frac{1}{2}\)

\(\frac{\log_3 9 - \log_2 8}{\log_3 9}\) 

= \(\frac{\log_3 3^2 - \log_2  2^3}{\log_3 3^2}\) 

= \(\frac{2 -3}{2}\)

= \(\frac{-1}{2}\)

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