Two groups of male students cast their vote on a particular proposal. The results are as follows:<table border=\"1\" cellpadding=\"0\" cellspacing=\"0\" style=\"width:40%\"><tr><td> </td><td>In favor</td><td>Against</td></tr><tr><td>Group A</td><td>128</td><td>32</td></tr><tr><td>Group B</td><td>96</td><td>48</td></tr></table>If a student is chosen at random, what is probability that he is against the proposal?

Two groups of male students cast their vote on a particular proposal. The results are as follows: In favor Against Group A 128 32 Group B 96 48 If a student is chosen at random, what is probability that he is against the proposal?

Two groups of male students cast their vote on a particular proposal. The results are as follows:

If a student is chosen at random, what is probability that he is against the proposal?

The correct answer is C. 5/19

Probability that the student is against the proposal

= \(\frac{32 + 48}{128 + 32 + 96 + 48}\)

= \(\frac{80}{304}\)

= \(\frac{5}{19}\)