If log\(_{10}\) 2 = m and log\(_{10}\) 3 = n, find log\(_{10}\) 24 in terms of m and n.

  • A 3m + n
  • B m + 3n
  • C 4mn
  • D 3mn

The correct answer is A. 3m + n

log\(_{10}\) 24 = log\(_{10}\) 8 \(\times\) log\(_{10}\) 3

where log\(_{10}\) 8 = 3 log\(_{10}\) 2 = 3 \(\times\) m

and log\(_{10}\) 3 = n

: log\(_{10}\) 24 = 3m + n

Previous question Next question