Simplify: (11\(_{two}\))\(^2\)

  • A 1001\(_2\)
  • B 1101\(_2\)
  • C 101\(_2\)
  • D 10001\(_2\)

The correct answer is A. 1001\(_2\)

(11\(_{two}\))\(^2\) = (11\(_2\) \(\times\) (11\(_2\)) = \({1 \times 2^1 + 1 \times 2^0} \times ({1 \times 2^1 + 1 \times 2^0})\)    = \({1 \times 2 + 1 \times 1} \times ({1 \times 2 + 1 \times 1})\) = \({2 + 1} \times ({2 + 1})\) = 3 \(\times\) 3  = 9\(_{10}\) or 1001\(_2\) from  
2
2 4 r1
2 2 r0
2 1 r0
  0 r1
Previous question Next question